BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Integers

Expert replies
Source: — Problem Solving |

by thephoenix » Sun Nov 29, 2009 8:44 pm
IMO 71
Join the discussion

by papgust » Sun Nov 29, 2009 10:25 pm
Take a maximum integer which is less than 144. Avoid 143 as it is a prime number.
So, consider 142. 142 has 2 prime factors => 2 and 71.

For a number less than 144 to have a 71 as prime factor, it is the number 71 itself.
So, GCD of 71 and 142 = 71 (Option D)
Join the discussion

by ssuarezo » Mon Nov 30, 2009 8:22 am
Hi:

I always get confused with the untold part. The stem question makes no restrictions about primes.
Question: why can't be 143 (143x1), even if prime, it would be the greatest number (as asked).

Thank you,
Silvia
Join the discussion

by papgust » Mon Nov 30, 2009 8:46 am
When you have 143 and any other number (say 71), GCD of 143 and 71 will be 1. Because they have only a greatest common factor of 1. 143 has only 2 factors - 1, 143. 143 cannot be a factor for some other integer less than 144.

Remember, we are asked to find the greatest possible common divisor. So, we are ignoring 143 in this problem
Join the discussion

by thephoenix » Mon Nov 30, 2009 8:54 am
ssuarezo wrote:Hi:

I always get confused with the untold part. The stem question makes no restrictions about primes.
Question: why can't be 143 (143x1), even if prime, it would be the greatest number (as asked).

Thank you,
Silvia
for 143 and 1 , 143 cant be the greatest common divisor as 143 doesnt divide 1 the GCD in this case will be 1

HTH
Join the discussion

by Ian Stewart » Mon Nov 30, 2009 10:01 am
143 is not prime; it is equal to 11x13.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by ssuarezo » Mon Nov 30, 2009 11:05 am
Thank you Ian, Phoenix and Papgust.
True. They asked for the greatest common divisor, not the greatest number, and even if 143 is not prime ( didn't see it!), 11 and 13 are much lower than 71. I have to read carefully.
Thank you,
Silvia.
Join the discussion