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Integers

Expert replies
by ketkoag » Mon Mar 30, 2009 8:31 am
If y is an integer and y = |x| + x, is y = 0?
(1) x < 0
(2) y < 1

OA: D
How??
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Source: — Data Sufficiency |

by rs2010 » Mon Mar 30, 2009 9:42 am
Eq will give

y=2x if x>0
=0 if x<0

A says X<0 so you know y = 0

B says Y<0, since it is an interger so lets take integer less than 0
which is possible when X is less than 0.


SO D.
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by cm47323 » Mon Mar 30, 2009 9:47 am
We have two possibilites
If x is negative, y = abs(x) + x = 0, one x is positive, the other negative
If x is positive, y = abs (x) + x = 2x

(1) x < 0. y=0. logic above, Sufficient
(2) y < 1. This tripped me up initially, but the key is that y is an integer, so y<=0. Since y can't be negative. y=0. Sufficient

D
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by ketkoag » Mon Mar 30, 2009 10:47 am
please lemme know why y can't be negative if we consider statement 2 coz if x is negative then y is negative. Please elaborate.
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by cm47323 » Mon Mar 30, 2009 11:00 am
If x is negative, y = abs(x) + x = 0, one x is positive, the other negative
If x is positive, y = abs (x) + x = 2x

By this logic, Y can never be negative. It has nothing to do with the information in (2). 2 just mandates that y=0
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