Whats the fastest approach for problems like these?
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Maxx
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Cramya, your method is the easiest and fastest one. All we need to do is to prove the statement with a number and move forward.cramya wrote:Not sure if this is the easiest way but this is one way
Stmt I)
k is divisible by 4
8 div by 4 not a sqaure of an integer
16 div by 4 square if an integer
INSUFF
Stmt II
2*3*5*7 has 4 different prime factors but not square of an integer
2^2 * 3 ^ 2 * 5 ^2 * 7 ^2 has 4 different prime factors but is the square of n integer
INSUFF
Stmt I and Stmt II
2^2 * 3 ^ 2 * 5 ^2 * 7 ^2 satisfies both statements and is sqaure of an integer
2^3 3 ^2 5 ^2 7 ^2 satisfies both statements and is not square of an
integer
E)
Hope I have not missed something! Let me know if u still have questions