BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Integer Digit Problem

Expert replies
by wcheng57 » Fri Jun 04, 2010 9:54 pm
This was a real GMAT problem from an old GMAT Test Paper exam.

How many integers between 324,700 and 458,600 have tens digit 1 and units digit 3?

a) 10,300

b) 10,030

c) 1353

d) 1352

e) 1339


E is the correct answer. Could someone explain how one would do this problem in under 2 minutes? Thanks.
Join the discussion
Source: — Problem Solving |

by pradeepkaushal9518 » Fri Jun 04, 2010 10:06 pm
imo E is answer 1339

as 458600-324700=133900

in every 100 there is one no having 13 so 133900/100=1339

it takes me only 1 min
Join the discussion

by iikarthik » Fri Jun 04, 2010 11:55 pm
The unit disgit -3 repeats itself for every 10 consecutive nos
But the tenth digit -1 repeats itself only for every 100 consecutive nos.
We need both the 1 and 3 to be present for that number to get counted.
so the counting of 3 can be ignored it can't be counted without the presence of digit 1 that repeats once in 100 numbers.

so 458600-324700 = 133900

since the required combination repeats itself once in 100 numbers

133900/100, we get 1339
Join the discussion