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Integer coordinates

Expert replies
by kackerarnav » Wed Jan 15, 2014 1:27 am
A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?


A) 4

B) 6

C) 8

D) 10

E) 12

The solution provided to this involves finding the all the possible integer coordinates of the other vertex side whose first is at origin (resulting in a length of 10). [-8,-6 -10,0 etc.]. However, implicit in the solution is the assumption that if these two vertices are made of integers, the others will be as well. This isn't obvious to me.

Could some shed some clarity on why that must be true?

Thanks, guys

Arnav
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Source: — Problem Solving |

by GMATGuruNY » Wed Jan 15, 2014 2:13 am
A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an area of 100. If all coordinates of the vertices must be integers, how many different ways can this square be drawn?
A)4
B)6
C)8
D)10
E)12
Step 1: If area = 100, side = 10.
Step 2: Recognize that the hypotenuse of a 6-8-10 triangle is 10.
Step 3: Plot coordinate pairs using every possible combination of (±6,±8), (±8,±6),(0,±10) and (±10,0).
Step 4: Use the plotted points to draw as many squares as possible, making sure that each square has a vertex at the origin:

Image

The figure above shows that the number of possible squares = 12.

The correct answer is E.
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