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by yvonne12 » Sun Mar 04, 2007 12:14 pm
the main ingredient in a certain prescription drug capsules cost $500 per kilogram. If each capsule contains 600 millograms of the ingredient. what is the cost of the main ingredient (1 kilogram=10^6)

ans. 30

please explain
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by jayhawk2001 » Sun Mar 04, 2007 5:50 pm
If 10^6 mg => 500$

600 mg = 500/(10^6) * 600 = .3$
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by Scott@TargetTestPrep » Mon Jun 25, 2018 11:16 am
yvonne12 wrote:the main ingredient in a certain prescription drug capsules cost $500 per kilogram. If each capsule contains 600 millograms of the ingredient. what is the cost of the main ingredient (1 kilogram=10^6)
We can use a proportion to solve this problem. Letting x be the cost, in dollars, per 600-mg capsule, we have

$500/1 kg = $x/600 mg

Before we can cross multiply, we need the denominators to have the same units. Since we are given 1 kg = 10^6 mg, we have:

$500/10^6 mg = $x/600 mg

500/10^6 = x/600

(10^6)(x) = 500(600)

1,000,000(x) = 300,000

10x = 3

x = 0.3

Thus, the cost is $0.30 per capsule.

Answer: $0.30 or 30¢

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