aroon7 wrote:If -2x > 3y, is x negative?
1) y>0
2) 2x + 5y - 20 = 0
(1) If y is positive and -2x > 3y, then -2x > 0. Therefore, x must be negative: sufficient.
(2) 2x + 5y = 20. So, at least one of x and y must be positive (for two numbers to have a positive sum, at least one must be positive, since neg + neg = neg).
Well, if y is positive, then as we saw from statement (1), x must be negative... so we can get a "yes" answer.
Part of me wants to say that we should be able to get a positive x too, but a bigger part of me thinks that the ratio of x:y in statement (2) makes it impossible for a positive value of x (which would lead to a negative value of y due to the inequality) to hold true. So my gut is saying that (2) is also sufficient on its own, although I'm having trouble proving it!
Someone feel free to prove me right or wrong!
Good solution above, hit enter before I did!
Last edited by Stuart@KaplanGMAT on Sun Jan 25, 2009 7:48 pm, edited 1 time in total.