If x and y are integers such that x < y < 0, what is x - y?
(1) (x + y)(x - y) = 5
(2) xy = 6
OA later
(1) (x + y)(x - y) = 5
(2) xy = 6
OA later
--Anand--
If x<y<0, x<0 and y<0.
(1) Can be written as (x - y) = 5 / (x+y). This indicates that since 5 / (x+y) has no one unique value for x<y<0, then statement I is NS
(2)
Keep in my x and y are both negative. This means the ONLY possible combinations such that xy=6 and x<y<0 are as follows:
If x=-3 y=-2, then x - y = -1
If x=-6 y=-1, then x - y = -5
TOGETHER
Use the data from both statements together.
If x=-3 y=-2, then x - y = -1 ; does (x - y) = 5/(x+y)? Does -1=5/(-5). Yes. We now know that x-y can equal -1.
If x=-6 y=-1, then x - y = -5 ; does (x - y) = 5/(x+y)? Does -5=5/(-7). No. This cannot be a solution.
Only one solution is possible and unique, so the answer should be C.
