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Inequality - MGMAT

Expert replies
by Lifetron » Wed Feb 13, 2013 11:38 pm
If (a^2)*b > 1 and b < 2, which of the following could be the value of a?

A)1/2
B)1/4
C)-(1/2)
D)-2
E)2/3

OA D

Source MGMAT
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Source: — Problem Solving |

by Anurag@Gurome » Thu Feb 14, 2013 1:17 am
gughanbose wrote:If (a^2)*b > 1 and b < 2, which of the following could be the value of a?
a²b > 1 ---> a² and b are of same sign
As a² is always positive, b is also positive.

Hence, a² > 1/b and 1/b > 1/2
Hence, a² > 1/2

Only option D works.

The correct answer is D.
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by ceilidh.erickson » Thu Feb 14, 2013 10:36 am
We can also work backwards from the answer choices here, to see which one works:

A. If a=1/2, then (1/4)*b has to be greater than 1, which means b has to be greater than 4. But b has to be less than 2, so this doesn't work.

B. If a=1/4, then (1/16)*b has to be greater than 1, which means b has to be greater than 16. But b has to be less than 2, so this doesn't work.

C. a^2 here would be the same as in A. Doesn't work.

D. If a=-2, then (4)*b has to be greater than 1, then b has to be greater than 1/4. b can be any number between 1/4 and 2. This works!

E. If a=2/3, then (4/9)*b has to be greater than 1, so b has to be greater than 9/4. 9/4 is greater than 2, so this doesn't work.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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by GMATGuruNY » Thu Feb 14, 2013 1:52 pm
gughanbose wrote:If (a^2)*b > 1 and b < 2, which of the following could be the value of a?

A)1/2
B)1/4
C)-(1/2)
D)-2
E)2/3

OA D

Source MGMAT
Since a²b > 1, we know that a²≠0.
Thus, we can safely divide each side of the inequality by a², which cannot be negative:
b > 1/a².

Linking together 2>b and b>1/a², we get:
2 > b > 1/a²
2 > 1/a²
a² > 1/2.
Of the five answer choices, only a=-2 is viable.

The correct answer is D.
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