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inequality and variable

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by Gurpinder » Fri Sep 03, 2010 10:38 am
X^2 < 4, what are the possible values for x?

shouldnt x = -2

because x could be 2,-2 but only -2 is les than 2 as in the question?

2<2
-2<2 <<< this should be the answer right?
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by debmalya_dutta » Fri Sep 03, 2010 11:00 am
Gurpinder wrote:X^2 < 4, what are the possible values for x?

shouldnt x = -2

because x could be 2,-2 but only -2 is les than 2 as in the question?

2<2
-2<2 <<< this should be the answer right?
X^2 < 4
X^2 - 2 ^2 < 0
(X+2)(X-2) < 0

so -2< X < +2 .. All values between -2(excluding) and +2 (excluding)
@Deb
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by Gurpinder » Fri Sep 03, 2010 11:02 am
debmalya_dutta wrote:
Gurpinder wrote:X^2 < 4, what are the possible values for x?

shouldnt x = -2

because x could be 2,-2 but only -2 is les than 2 as in the question?

2<2
-2<2 <<< this should be the answer right?
X^2 < 4
X^2 - 2 ^2 < 0
(X+2)(X-2) < 0

so -2< X < +2 .. All values between -2(excluding) and +2 (excluding)
AHH...thx

i was just taking the sq. root of both sides. is that wrong?
“Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress.”
- Alfred A. Montapert, Philosopher.
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by debmalya_dutta » Fri Sep 03, 2010 11:16 am
Gurpinder wrote:
debmalya_dutta wrote:
Gurpinder wrote:X^2 < 4, what are the possible values for x?

shouldnt x = -2

because x could be 2,-2 but only -2 is les than 2 as in the question?

2<2
-2<2 <<< this should be the answer right?
X^2 < 4
X^2 - 2 ^2 < 0
(X+2)(X-2) < 0

so -2< X < +2 .. All values between -2(excluding) and +2 (excluding)
AHH...thx

i was just taking the sq. root of both sides. is that wrong?
taking square root also works but then you should build the inequality as
|X|< 2
Its just that its a cleaner way to approach (ofcourse per me) ..You are free to disagree :)
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by Gurpinder » Fri Sep 03, 2010 11:19 am
THX
“Do not confuse motion and progress. A rocking horse keeps moving but does not make any progress.”
- Alfred A. Montapert, Philosopher.
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