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by winnerhere » Sat Oct 17, 2009 4:01 am
If 2x + 3y > 6 and y-x > -1 ,the sign of which of the following expressions can be uniquely determined?

A. 3x + 7y

B. 4x + 11y

C. x+y

1.Only A and B

2.Ony B and C

3.Only C and A

4.A,B and C

5.None of these
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by sanjana » Mon Oct 19, 2009 10:09 pm
IMO : D

Whats the OA,if i'm correct will explain.
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by mpaudena » Wed Oct 21, 2009 5:18 am
sanjana wrote:IMO : D

Whats the OA,if i'm correct will explain.
Can you explain anyway? I got E.
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by JeffB » Wed Oct 21, 2009 8:59 am
I got D too. Solved for x and y
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Re: Inequalities

by uttam.albela » Thu Oct 22, 2009 7:58 pm
winnerhere wrote:If 2x + 3y > 6 and y-x > -1 ,the sign of which of the following expressions can be uniquely determined?

A. 3x + 7y

B. 4x + 11y

C. x+y

1.Only A and B

2.Ony B and C

3.Only C and A

4.A,B and C

5.None of these
Now add 2x+3y>6
2y-2x> -2
We get 5y > 4
y> 4/5

Put this in first equation
2x > 6 - (3*(4/5))
x > 9/5

Using these values for x and y, we can determine signs for all the above equations.
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