ind the range of values of x that satisfy the inequality (x2

$$\frac{\left(x^2-4\right)}{\left(x-5\right)\left(x-9\right)}<0$$
$$where\ \left(x^2-4\right)=\left(x+2\right)\left(x-2\right)\ and\ \left(x^2-9\right)=\left(x+3\right)\left(x-3\right)$$
$$Therefore,\ \frac{\left(x+2\right)\left(x-2\right)}{\left(x-5\right)\left(x+3\right)\left(x-3\right)}\ <0$$
$$Required\ range\ =>\ x<-3\ or\ -2<x<2\ or\ 3<x<5$$

Answer = option D