BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

income tax

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Mon Jun 04, 2007 7:37 am
Thanked: 6 times

by sonu_thekool » Wed Jan 07, 2009 8:24 am
I think the answer is C - 50 + 3I/100

This is how I approached it.

Lets call the Income of the person as I.

2% of I would be 2I/100

Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = 50*100 / 100 = 50

1% of I would be I/100

Adding them all up = 50 + 3I/100

Is this the right approach ? What is the OA ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 940
Joined: Tue Aug 26, 2008 3:22 amFollowed by: 1 member
Thanked: 55 times

by iamcste » Wed Jan 07, 2009 8:56 am
sonu_thekool wrote:I think the answer is C - 50 + 3I/100
Did you mean B
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 9:06 am
sonu_thekool wrote:I think the answer is C - 50 + 3I/100



Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = [color=red]50[/color]*100 / 100 = 50

? What is the OA ?

From where did u got this 50 ???????????????
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Mon Jun 04, 2007 7:37 am
Thanked: 6 times

by sonu_thekool » Wed Jan 07, 2009 9:07 am
iamcste wrote:
sonu_thekool wrote:I think the answer is C - 50 + 3I/100
Did you mean B
Sorry, I meant B.

What is the OA ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 259
Joined: Thu Jan 18, 2007 8:30 pm
Thanked: 16 times

by amitabhprasad » Wed Jan 07, 2009 10:03 am
I am getting "C"
50+I/40
Av of 100+1%of I = 50+I/200
Add 2% of I to it = 2*I/100+I/200+50
= I/40+50
Whats OA ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Mon Jun 04, 2007 7:37 am
Thanked: 6 times

by sonu_thekool » Wed Jan 07, 2009 11:01 am
amitabhprasad wrote:I am getting "C"
50+I/40
Av of 100+1%of I = 50+I/200
Add 2% of I to it = 2*I/100+I/200+50
= I/40+50
Whats OA ?
You have the same approach as mine but

Av of 100 + 1% of I = 50 + I/100 (Not 50 + I/200)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 11:09 am
vivek.kapoor83 wrote:
sonu_thekool wrote:I think the answer is C - 50 + 3I/100



Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = [color=red]50[/color]*100 / 100 = 50

? What is the OA ?

From where did u got this 50 ???????????????
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 11:10 am
amitabhprasad wrote: Av of 100+1%of I = 50+I/200
?
can u explain the above step, how u got 50 ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Mon Jun 04, 2007 7:37 am
Thanked: 6 times

by sonu_thekool » Wed Jan 07, 2009 11:13 am
The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 11:30 am
sonu_thekool wrote:The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.

Im just readin it 1st time..strange. i didnt knw that
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 594
Joined: Thu Aug 14, 2008 11:51 pm
Thanked: 12 times

by nervesofsteel » Wed Jan 07, 2009 11:47 am
vivek.kapoor83 wrote:
sonu_thekool wrote:The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.

Im just readin it 1st time..strange. i didnt knw that

Vivek

is 50+3I/100 the OA..??

Approach by Sonu sounds good
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 11:55 am
OA is C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Mon Jun 04, 2007 7:37 am
Thanked: 6 times

by sonu_thekool » Wed Jan 07, 2009 11:59 am
vivek.kapoor83 wrote:OA is C
Can you please post any explanation given to show how the answer is 'C' -
50 + I/40 ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 833
Joined: Mon Aug 04, 2008 1:56 am
Thanked: 13 times

by vivek.kapoor83 » Wed Jan 07, 2009 12:06 pm
Sorry dear,
there are no explanation in GMAT prep
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply