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by sonu_thekool » Wed Jan 07, 2009 8:24 am
I think the answer is C - 50 + 3I/100

This is how I approached it.

Lets call the Income of the person as I.

2% of I would be 2I/100

Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = 50*100 / 100 = 50

1% of I would be I/100

Adding them all up = 50 + 3I/100

Is this the right approach ? What is the OA ?
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by iamcste » Wed Jan 07, 2009 8:56 am
sonu_thekool wrote:I think the answer is C - 50 + 3I/100
Did you mean B
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by vivek.kapoor83 » Wed Jan 07, 2009 9:06 am
sonu_thekool wrote:I think the answer is C - 50 + 3I/100



Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = [color=red]50[/color]*100 / 100 = 50

? What is the OA ?

From where did u got this 50 ???????????????
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by sonu_thekool » Wed Jan 07, 2009 9:07 am
iamcste wrote:
sonu_thekool wrote:I think the answer is C - 50 + 3I/100
Did you mean B
Sorry, I meant B.

What is the OA ?
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by amitabhprasad » Wed Jan 07, 2009 10:03 am
I am getting "C"
50+I/40
Av of 100+1%of I = 50+I/200
Add 2% of I to it = 2*I/100+I/200+50
= I/40+50
Whats OA ?
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by sonu_thekool » Wed Jan 07, 2009 11:01 am
amitabhprasad wrote:I am getting "C"
50+I/40
Av of 100+1%of I = 50+I/200
Add 2% of I to it = 2*I/100+I/200+50
= I/40+50
Whats OA ?
You have the same approach as mine but

Av of 100 + 1% of I = 50 + I/100 (Not 50 + I/200)
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by vivek.kapoor83 » Wed Jan 07, 2009 11:09 am
vivek.kapoor83 wrote:
sonu_thekool wrote:I think the answer is C - 50 + 3I/100



Arithmetic Mean (Average) of 100 units of currency = Sum of 100 units / 100 = [color=red]50[/color]*100 / 100 = 50

? What is the OA ?

From where did u got this 50 ???????????????
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by vivek.kapoor83 » Wed Jan 07, 2009 11:10 am
amitabhprasad wrote: Av of 100+1%of I = 50+I/200
?
can u explain the above step, how u got 50 ?
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by sonu_thekool » Wed Jan 07, 2009 11:13 am
The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.
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by vivek.kapoor83 » Wed Jan 07, 2009 11:30 am
sonu_thekool wrote:The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.

Im just readin it 1st time..strange. i didnt knw that
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by nervesofsteel » Wed Jan 07, 2009 11:47 am
vivek.kapoor83 wrote:
sonu_thekool wrote:The Average of a set = Sum of all the numbers / no. of terms in the set

A = S/n

So, Average of 100 items in the set = Sum of 100 terms / 100

Sum of consecutive numbers can be found by multiplying the number in the middle of the sequence (50) with the number of terms in the sequence

==> 50 * 100 ==> 5000

Average = 5000 / 100 = 50

This is how I got 50.

Im just readin it 1st time..strange. i didnt knw that

Vivek

is 50+3I/100 the OA..??

Approach by Sonu sounds good
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by vivek.kapoor83 » Wed Jan 07, 2009 11:55 am
OA is C
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by sonu_thekool » Wed Jan 07, 2009 11:59 am
vivek.kapoor83 wrote:OA is C
Can you please post any explanation given to show how the answer is 'C' -
50 + I/40 ?
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by vivek.kapoor83 » Wed Jan 07, 2009 12:06 pm
Sorry dear,
there are no explanation in GMAT prep
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