How many words, with or without meanings, can be constructed using all the letters in WONKCUL, such that there are exactly 3 letters between the 2 vowels?
(A) 5!
(B) 5! × 2!
(C) 6!
(D) 6! × 2!
(E) 6! × 3!
in WONKCUL, such that
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- sanju09
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Sanjeev K Saxena
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Sanjeev K Saxena
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- sanju09
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make sure all conditions were metkvcpk wrote:Fix 2 places for vowels and then fill the consonants.
So Consonants can be fille din 5! ways.
Vowels can be arranged in 2! ways.
Hence B.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- kvcpk
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My bad!! Answer should be 6!sanju09 wrote:make sure all conditions were metkvcpk wrote:Fix 2 places for vowels and then fill the consonants.
So Consonants can be fille din 5! ways.
Vowels can be arranged in 2! ways.
Hence B.
there are three possible places for the vowels.
So 3*2!*5! = 6!
Right this time?
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there are 5! possible ways for letters cos there are 5 letters in the wordssanju09 wrote:How many words, with or without meanings, can be constructed using all the letters in WONKCUL, such that there are exactly 3 letters between the 2 vowels?
(A) 5!
(B) 5! × 2!
(C) 6!
(D) 6! × 2!
(E) 6! × 3!
there are 3! possible ways for vowels
O---U-- ( 0 is in the first place)
if O is in the second place _O---U-
if O in the third place --O---U
we did the same with U ( just opposite it)
so there are 3!=1*2*3=6 possible ways for those place
thus total we have 6!
answer should be C