In the rectangular coordinate system above, the area of triangular region $PQR$ is

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VJesus12: Legendary Member; Posts: 2276; Joined: Sat Oct 14, 2017 6:10 amFollowed by: 3 members

by VJesus12 » Fri Dec 17, 2021 10:24 am

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In the rectangular coordinate system above, the area of triangular region $PQR$ is

(A) $12.5$
(B) $14$
(C) $10\sqrt2$
(D) $16$
(E) $25$

Answer: A

Source: GMAT Prep

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Source: Beat The GMAT — Problem Solving | Fri Dec 17, 2021 10:24 am

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Re: In the rectangular coordinate system above, the area of triangular region $PQR$ is

by Brent@GMATPrepNow » Fri Dec 17, 2021 12:39 pm

VJesus12 wrote: ↑
Fri Dec 17, 2021 10:24 am
IMAGE PT1.jpg

In the rectangular coordinate system above, the area of triangular region $PQR$ is

(A) $12.5$
(B) $14$
(C) $10\sqrt2$
(D) $16$
(E) $25$

Answer: A

Source: GMAT Prep

We're trying to find the area of triangle PQR.

Let's draw a rectangle around the triangle (as shown above) and then subtract from the rectangle's area (28) the areas of the 3 right triangles that surround the triangle in question.

We get the following:

So, the area of PQR = 28 - (3.5 + 6 + 6) = 12.5

Answer = A

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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