In the figure shown above, line segment QR has length 12,

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AAPL: Moderator; Posts: 2632; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Fri Aug 31, 2018 5:16 am

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In the figure shown above, line segment has length of 12, and rectangle MPQT is a square. If the area of rectangular region MPRS is 540, what is the area of rectangular region TQRS?

A. 144
B. 216
C. 324
D. 360
E. 396

OA B.

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Source: Beat The GMAT — Problem Solving | Fri Aug 31, 2018 5:16 am

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Jay@ManhattanReview: GMAT Instructor; Posts: 3008; Joined: Mon Aug 22, 2016 6:19 amFollowed by: 34 members; Location: Grand Central / New York; Thanked: 470 times

by Jay@ManhattanReview » Sun Sep 02, 2018 10:53 pm

AAPL wrote:Official Guide

In the figure shown above, line segment has length of 12, and rectangle MPQT is a square. If the area of rectangular region MPRS is 540, what is the area of rectangular region TQRS?

A. 144
B. 216
C. 324
D. 360
E. 396

OA B.

The question is posted correctly.

The correct version is this:

In the figure shown above, line segment QR has length of 12, and rectangle MPQT is a square. If the area of rectangular region MPRS is 540, what is the area of rectangular region TQRS?

Area of MPRS = Area of MPQT + Area of TQRS

Say the length of the square MPQT = x, thus, Area of MPQT = x^2

And, Area of TQRS = 12.x

So, 540 = x^2 + 12x => x = 18.

Area of TQRS = 12*18 = 216

The correct answer: B

Hope this helps!

-Jay
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Manhattan Review

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fskilnik@GMATH: GMAT Instructor; Posts: 1449; Joined: Sat Oct 09, 2010 2:16 pmFollowed by: 33 members; Thanked: 59 times

by fskilnik@GMATH » Mon Sep 03, 2018 4:35 am

AAPL wrote:Official Guide

In the figure shown above, line segment QR has length of 12, and rectangle MPQT is a square. If the area of rectangular region MPRS is 540, what is the area of rectangular region TQRS?

A. 144
B. 216
C. 324
D. 360
E. 396

\[? = S\]
\[540 = \frac{S}{{12}}\left( {12 + \frac{S}{{12}}} \right)\,\,\mathop = \limits^{x\,\,\left( {aux} \right)\,\, = \,\,\,S/12} \,\,\,x\left( {12 + x} \right)\]
\[540 = 54 \cdot 10 = 27 \cdot 2 \cdot 10 = {3^3} \cdot {2^2} \cdot 5\,\,\,\,\mathop \Rightarrow \limits^{12\,\,{\text{difference}}} \left\{ \begin{gathered}
\boxed{x = {3^2} \cdot 2 = 18} \hfill \\
12 + x = 3 \cdot 2 \cdot 5 = 30 \hfill \\
\end{gathered} \right.\]
\[\frac{S}{{12}} = x = 18\,\,\, \Rightarrow \,\,? = S = 12 \cdot 18 = 180 + 36 = 216\]

This solution follows the notations and rationale taught in the GMATH method.

Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8136; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Fri Sep 07, 2018 4:22 pm

AAPL wrote:Official Guide

In the figure shown above, line segment has length of 12, and rectangle MPQT is a square. If the area of rectangular region MPRS is 540, what is the area of rectangular region TQRS?

A. 144
B. 216
C. 324
D. 360
E. 396

Since PQMT is a square, we can let PQ = PM = n. Since QR = 12, PR = n + 12. Finally, since the area of rectangle MPRS is 540, we have:

n(n + 12) = 540

n^2 + 12n = 540

n^2 + 12n - 540 = 0

(n + 30)(n - 18) = 0

n = -30 or n = 18

Since n can't be negative, n = 18, and the area of square MPQT is 18 x 18 = 324. Thus, the area of rectangle TQRS is 540 - 324 = 216. (Or the area of rectangle TQRS is 18 x 12 = 216.)

Answer: B

Scott Woodbury-Stewart
Founder and CEO
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