VJesus12 wrote: ↑Sat Jan 01, 2022 1:15 pm
4.jpg
In the figure above, if \(\overline{AD}\) is parallel to \(\overline{BC},\) then \(\angle ADC=\)
\(A.\, 11^\circ\)
\(B.\, 22^\circ\)
\(C.\, 33^\circ\)
\(D.\, 46^\circ\)
\(E.\, 134^\circ\)
Answer:
C
Source: Princeton Review
First, since angles in a triangle must add to 180°, we can see that the missing angle in the red triangle must be
180° - (x + 44)°
Simplify this measurement to get
(136 - x)°
Finally, since AD is parallel to BC, we know that the two highlighted angles below must add to 180°.
So, we can write:
(136 - x)° + 2x° + 3x° = 180°
Simplify:
136 + 4x = 180
Subtract 136 from both sides: :
4x = 44
Solve:
x = 11
Our goal is to find the measurement of ∠ADC
Since ∠ADC = 3x°, we can replace
x with
11 to get: ∠ADC = 3x° = 3(
11)° =
33°
Answer: C
Brent Hanneson - Creator of GMATPrepNow.com
