M7MBA wrote: ↑Sun Nov 28, 2021 1:16 am
1.jpg
In the figure above, if \(AD\) is parallel to \(BC,\) then \(\angle ADC=\angle ADC=\)
A. \(11^{\circ}\)
B. \(22^{\circ}\)
C. \(33^{\circ}\)
D. \(46^{\circ}\)
E. \(134^{\circ}\)
Answer:
C
Source: Princeton Review
First, since angles in a triangle must add to 180°, we can see that the missing angle in the red triangle must be
180° - (x + 44)°
Simplify this measurement to get
(136 - x)°
Finally, since AD is parallel to BC, we know that the two highlighted angles below must add to 180°.
So, we can write:
(136 - x)° + 2x° + 3x° = 180°
Simplify:
136 + 4x = 180
Subtract 136 from both sides: :
4x = 44
Solve:
x = 11
Our goal is to find the measurement of ∠ADC
Since ∠ADC = 3x°, we can replace
x with
11 to get: ∠ADC = 3x° = 3(
11)° =
33°
Answer: C
Brent Hanneson - Creator of GMATPrepNow.com
