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In the diagram above, line \(PQ\) is tangent to the circle,

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by M7MBA » Fri Dec 13, 2019 11:11 am
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In the diagram above, line \(PQ\) is tangent to the circle, and the measure of arc \(PR\) is \(70°.\) What is the measure of \(∠PQR?\)

A. \(15°\)
B. \(20°\)
C. \(25°\)
D. \(30°\)
E. \(35°\)

[spoiler]OA=B[/spoiler]

Source: Magoosh
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by dsan6422 » Mon Dec 16, 2019 6:04 pm
Hope this helps.

https://youtu.be/BPil_CBN5J4
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by Pyunika » Tue Dec 17, 2019 10:52 am
angle p makes 90 degree since it is the tangent to the circle.
angle r is given as 70 degree
and sum of all the angles in the triangle should be 180. thus angle pqr equals 20 degree
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by Brent@GMATPrepNow » Wed Dec 18, 2019 6:20 am
M7MBA wrote:Image

In the diagram above, line \(PQ\) is tangent to the circle, and the measure of arc \(PR\) is \(70°.\) What is the measure of \(∠PQR?\)

A. \(15°\)
B. \(20°\)
C. \(25°\)
D. \(30°\)
E. \(35°\)
There's a real nice Circle Property rule that says: A line tangent to a circle will be perpendicular to the line passing through the center and the point of tangency
This means ∠OPQ = 90°
We are also told that ∠OPR = 70°

Since all three angles in a triangle must add to 180°, we can conclude that ∠PQR = 20°

Answer: B

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Brent
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by Scott@TargetTestPrep » Wed Jan 01, 2020 6:43 pm
M7MBA wrote:Image

In the diagram above, line \(PQ\) is tangent to the circle, and the measure of arc \(PR\) is \(70°.\) What is the measure of \(∠PQR?\)

A. \(15°\)
B. \(20°\)
C. \(25°\)
D. \(30°\)
E. \(35°\)

[spoiler]OA=B[/spoiler]

Source: Magoosh
While we are not told that it is so, we assume that O is the center because otherwise, the answer cannot be determined from the given information.

Since arc PR = 70 degrees, then the intercepted central angle (angle ROP) is also 70 degrees. Furthermore, since line PQ is tangent to the circle, angle OPQ = 90 degrees. Therefore, angle PQR = 180 - 70 - 90 = 20 degrees.

Answer: B

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