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In the diagram above, line \(JX\) is parallel to line \(KY.\) If the area of triangle \(KYZ\) is 18 square feet, what is

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by VJesus12 » Thu Jun 04, 2020 7:23 am

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TriangleJXZ.png
(NOTE: Not drawn to scale)

In the diagram above, line \(JX\) is parallel to line \(KY.\) If the area of triangle \(KYZ\) is 18 square feet, what is the length of side \(JX?\)

(1) Side \(JZ\) measures \(18\sqrt2\)

(2) Triangle \(KYZ\) is isosceles

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
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