In the biology lab of "Jefferson" High School ther

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AAPL: Moderator; Posts: 2632; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Tue Aug 21, 2018 5:46 am

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Economist GMAT

In the biology lab of "Jefferson" High School, there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

AO E.

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Source: Beat The GMAT — Problem Solving | Tue Aug 21, 2018 5:46 am

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Brent@GMATPrepNow: GMAT Instructor; Posts: 16207; Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members; Location: Vancouver, BC; Thanked: 5254 times; GMAT Score:770

by Brent@GMATPrepNow » Tue Aug 21, 2018 11:04 am

AAPL wrote:Economist GMAT

In the biology lab of "Jefferson" High School, there are 0.037 x 10^5 germs, equally divided among 74000 x 10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

AO E.

Germs per dish = (total number of germs)/(total number of dishes)

total number of germs = 0.037 x 10^5
= 3700 [moved the decimal point 5 spaces to the LEFT to get 3700]

total number of dishes = 74000 x 10^(-3)
= 74 [moved the decimal point 3 spaces to the RIGHT to get 3700]

So, Germs per dish = (3700)/(74)
= (37)(100)/(37)(2)
= 100/2
= 50

Answer: E

Cheers,
Brent

Brent Hanneson - Creator of GMATPrepNow.com

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fskilnik@GMATH: GMAT Instructor; Posts: 1449; Joined: Sat Oct 09, 2010 2:16 pmFollowed by: 33 members; Thanked: 59 times

by fskilnik@GMATH » Tue Aug 21, 2018 11:42 am

<p>

</p>
In the biology lab of "Jefferson" High School, there are 0.037 x 10^5 germs, equally divided among 74000 x 10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

The solution above follows the notations and rationale taught in the <b>GMATH</b> method.

Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8136; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Thu Aug 23, 2018 4:03 pm

AAPL wrote:Economist GMAT

In the biology lab of "Jefferson" High School, there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?

A. 10
B. 20
C. 30
D. 40
E. 50

The number of germs that live happily in a single dish is:

0.037*10^5/74,000*10^(-3)

(0.037 x 100,000)/(74,000 x 1/1000)

3700/74 = 50

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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