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by pzazz12 » Wed Oct 06, 2010 11:31 pm
In a small snack shop, the average (arithmetic mean) revenue was $400 per day over a 10-day period. During this period, if the average daily revenue was $360 for the first 6 days,what was the average daily revenue for the last 4 days?

A. $420
B. $440
C. $450
D. $460
E. $480
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by treker » Thu Oct 07, 2010 12:02 am
Answer is D

Total revenue over the 10 day period: 400 * 10 = 4000
Total rev for first 6 days: 360*6 = 2160
Total revenue for the next 4 days = 4000 -2160 = 1840

Therefore, Avg revenue for the next 4 days = 1840/4 = 460
Thanks!
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by Testluv » Thu Oct 07, 2010 1:46 am
We can also solve this through the balanced scale concept.

The overall average is $400.

The first 6 days' average is $360. So, on each of these 6 days, we are short $40 from the average (400-360). Thus, we have to make up 6*$40 = $240.

So, we have to "spread" an extra $240 across the last 4 days. That's an extra 240/4 = $60 beyond $400. And, 60 + 400 = 460.
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by pzazz12 » Sat Oct 09, 2010 12:12 am
treker wrote:Answer is D

Total revenue over the 10 day period: 400 * 10 = 4000
Total rev for first 6 days: 360*6 = 2160
Total revenue for the next 4 days = 4000 -2160 = 1840

Therefore, Avg revenue for the next 4 days = 1840/4 = 460

thank you....i understood how to solve it............
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