Vincen wrote:In a sample of college students, 40 percent are third year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?
(A) 3/4
(B) 2/3
(C) 4/7
(D) 1/2
(E) 3/7
OA is D.
The problems that involve percentages are very difficult to me. Experts, how can I solve these kind of problems in a way easy to understand?
Say there are a total of a total of 100 students ( I year, II year, and III year)
Number of III year students = 40% of 100 = 40
Number of students who are not II year students = 70% of 100 = 70
=> Number of II year students = 100 - 70 = 30
=> Number of I year and III year students combined = 70
=> Number of I year students = 70 - Number of III year students = 70 - 40 = 30
Thus, the number of I year and II year students combined = 30 + 30 = 60
Thus, (Number of II year students) / (Number of I year and II year students combined) = 30 / 60 = 1/2.
The correct answer:
D
Hope this helps!
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