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In a race of 6 horses A, B, C, D, E and F, what is the prob

Expert replies
by GMATinsight » Sun Apr 01, 2018 12:11 am
In a race of 6 horses A, B, C, D, E and F, what is the probability of A finishing ahead of B and C both? There are no ties between any two horses.

A) 1/2
B) 1/3
C) 1/6
D) 1/12
E) 1/15

Source: www.GMATinsight.com

Answer: Option B
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Source: — Problem Solving |

race

by GMATGuruNY » Sun Apr 01, 2018 2:06 am
GMATinsight wrote:In a race of 6 horses A, B, C, D, E and F, what is the probability of A finishing ahead of B and C both? There are no ties between any two horses.

A) 1/2
B) 1/3
C) 1/6
D) 1/12
E) 1/15
Within the race, the number of possible orderings for A, B and C = 3! = 6.
Since there are 2 orderings in which A appears before both B and C -- ABC and ACB -- we get:
P(A appears before both B and C) = 2/6 = 1/3.

The correct answer is B.
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by Scott@TargetTestPrep » Thu May 23, 2019 4:15 pm
GMATinsight wrote:In a race of 6 horses A, B, C, D, E and F, what is the probability of A finishing ahead of B and C both? There are no ties between any two horses.

A) 1/2
B) 1/3
C) 1/6
D) 1/12
E) 1/15

Source: www.GMATinsight.com

Answer: Option B
Since we only care about A finishing ahead of B and C, we can ignore the other horses. If we only have three horses A, B and C, the ordering of the 3 horses can be:

ABC, ACB, BAC, BCA, CAB, CBA

We see that of the 6 orderings, only (the first) 2 have A ahead of B and C, therefore, the probability is 2/6 = 1/3.

Answer: B

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by Scott@TargetTestPrep » Thu May 23, 2019 4:15 pm
GMATinsight wrote:In a race of 6 horses A, B, C, D, E and F, what is the probability of A finishing ahead of B and C both? There are no ties between any two horses.

A) 1/2
B) 1/3
C) 1/6
D) 1/12
E) 1/15

Source: www.GMATinsight.com

Answer: Option B
Since we only care about A finishing ahead of B and C, we can ignore the other horses. If we only have three horses A, B and C, the ordering of the 3 horses can be:

ABC, ACB, BAC, BCA, CAB, CBA

We see that of the 6 orderings, only (the first) 2 have A ahead of B and C, therefore, the probability is 2/6 = 1/3.

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

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