In a nationwide poll, N people were interviewed. If 1/4 of them answered "yes" to question 1, and of those, 1/3 answered "yes" to question 2, which of the following expressions represents the number of people interviewed who did NOT answer "yes" to both questions?
A. N/7
B. 6N/7
C. 5N/12
D. 7N/12
E. 11N/12
[spoiler]OA=E[/spoiler]
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In a nationwide poll, N people were interviewed. If 1/4
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GMATinsight
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People to answered Yes to Q-1 = N/4M7MBA wrote:In a nationwide poll, N people were interviewed. If 1/4 of them answered "yes" to question 1, and of those, 1/3 answered "yes" to question 2, which of the following expressions represents the number of people interviewed who did NOT answer "yes" to both questions?
A. N/7
B. 6N/7
C. 5N/12
D. 7N/12
E. 11N/12
[spoiler]OA=E[/spoiler]
Source: Veritas Prep
People who answered Yes to both Q-1 and Q-2 = (1/3)*(N/4) = N/12
i.e. People who did NOT answer yes to BOTH Q-1 and Q-2 = N - (N/12) = 11N/12
Answer: Option E
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Let N=12.M7MBA wrote:In a nationwide poll, N people were interviewed. If 1/4 of them answered "yes" to question 1, and of those, 1/3 answered "yes" to question 2, which of the following expressions represents the number of people interviewed who did NOT answer "yes" to both questions?
A. N/7
B. 6N/7
C. 5N/12
D. 7N/12
E. 11N/12
Number who answered yes to question 1 = (1/4)12 = 3.
Number who also answered yes to question 2 = (1/3)3 = 1.
Number who didn't answer yes to both questions = 12-1 = 11. This is our target.
Now we plug N=12 into the answers to see which yields our target of 11.
Only E works:
(11/12)N = (11/12)12 = 11.
The correct answer is E.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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