in a game

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clock60: Legendary Member; Posts: 759; Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members; Thanked: 85 times

by clock60 » Sat Nov 20, 2010 10:16 am

hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C

i have little idea how to couple but i am wrong.... where?
if there 24 players, the number of teams and the number of players in every team can be
(4,6) (6,4) (3,8) (8,3)
(1) 24+13=37-1=36-the number of players so possible pairs are
(3,12) (12,3) (6,6) ( 4,9) (9,4) insuff
(2) 24+7=31-1=30 (5,6) (6,5) (3,10) (10,3) again insuff
now i start to understand but not sure
together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff
guys i will be happy to observe other solutions or ways of thinking

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Source: Beat The GMAT — Data Sufficiency | Sat Nov 20, 2010 10:16 am

shovan85: Community Manager; Posts: 991; Joined: Thu Sep 23, 2010 6:19 amFollowed by: 24 members; Location: Bangalore, India; Thanked: 146 times

by shovan85 » Sat Nov 20, 2010 10:24 am

clock60 wrote: together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff

You also got E then why did you mention you got C.

From your approach it is clear that there can be 3 teams or 6 teams. Hence we cannot say a concrete answer for total number of teams. So both insufficient.

If the problem is Easy Respect it, if the problem is tough Attack it

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clock60: Legendary Member; Posts: 759; Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members; Thanked: 85 times

by clock60 » Sat Nov 20, 2010 10:30 am

hi shovan85
initially i got C, and picked up wrong answer, but while posting the problem i got what is wrong in my reasoning
can you share your way of solving this task?

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Night reader: Legendary Member; Posts: 1337; Joined: Sat Dec 27, 2008 6:29 pmFollowed by: 10 members; Thanked: 127 times

by Night reader » Sat Nov 20, 2010 5:44 pm

So luuung...

x=teams, y=players

(2+x)(2+y)=24

st1. (2+x)(2+y+12)=24+12, value for 'y' is positive, 'x' is negative
st2. (2+x)(2+y+6)=24+6, the same here y=22, x=-1

Can not solve for two variables with either statement - E

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goyalsau: Legendary Member; Posts: 866; Joined: Mon Aug 02, 2010 6:46 pm; Location: Gwalior, India; Thanked: 31 times

by goyalsau » Sun Nov 21, 2010 1:41 am

clock60 wrote:hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C

We can have 3 teams , 4 teams , 6 teams 8 teams

3 teams , 4 teams , 6 teams 8 team

8 players , 6 players 4 players 3 players

12 New players can be added in any of the first 3 combinations
as

3 teams
4 players each team

4 teams
3 players each team

6 teams
2 players each team

II statement { 6 players }

3 teams
2 players each team

6 teams
1 players each team

Rest of the possibilities are not possible

So the answer should be E

Saurabh Goyal
[email protected]
-------------------------

EveryBody Wants to Win But Nobody wants to prepare for Win.

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diebeatsthegmat: Legendary Member; Posts: 1119; Joined: Fri May 07, 2010 8:50 amFollowed by: 3 members; Thanked: 29 times

by diebeatsthegmat » Sun Nov 21, 2010 8:07 pm

clock60 wrote:hi guys, confused with this one
In order to play a certain game, 24 players must be split into n teams, with each team having an equal number of players. If there are more than two teams, and if each team has more than two players, how many teams are there?
(1)If thirteen new players join the game, one must sit out so that the rest can be split up evenly among the teams.
(2) If seven new players join the game, one must sit out so that the rest can be split up evenly among the teams.
oa is E but i got C

i have little idea how to couple but i am wrong.... where?
if there 24 players, the number of teams and the number of players in every team can be
(4,6) (6,4) (3,8) (8,3)
(1) 24+13=37-1=36-the number of players so possible pairs are
(3,12) (12,3) (6,6) ( 4,9) (9,4) insuff
(2) 24+7=31-1=30 (5,6) (6,5) (3,10) (10,3) again insuff
now i start to understand but not sure
together
the number players can be (3,12) (3,10) with 3 players or (6,6) (6,5) with 6 players so also both insuff
guys i will be happy to observe other solutions or ways of thinking

i just solved this date logically
to find how many team there are, we have to find how many people for each team
1. 24+13 =33 -1 ( one must sit out of the game) =32
32 can divide into so many team which the number of people are even. For example: 8 teams with 4 people in each or 4 team with 8 peole in each : so insufficient
2/ 24+7 ( the same as 1) in sufficicent
1+2 can tell nothing

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