In a certain sequence, the first term is 1, and each successive term is 1 more than the reciprocal of the term that

$$T_{n\ }=1+\left(reciprocal\ of\ T_{n-1}\right)$$
$$T_1=1$$
$$T_2=1+\left(reciprocal\ of\ T_1\right)$$
$$T_3=1+\left(reciprocal\ of\ T_2\right)$$
$$T_4=1+\left(reciprocal\ of\ T_3\right)$$
$$T_5=1+\left(reciprocal\ of\ T_4\right)$$
$$=>T_1=1$$
$$T_2=1+1=2$$
$$T_3=1+\frac{1}{2}=\frac{3}{2}$$
$$T_4=1+\frac{2}{3}=\frac{5}{3}$$
$$T_5=1+\frac{3}{5}=\frac{8}{5}$$

Answer = C