In a certain corporation, there are 300 male employees and 100

BTGModeratorVI wrote: ↑

Thu Aug 27, 2020 12:13 pm

In a certain corporation, there are 300 male employees and 100 female employees. It is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 400 employees is chosen at random, what is the probability this employee has an advanced degree or is female?

A. 1/20
B. 1/10
C. 1/5
D. 2/5
E. 3/4

Answer: D
Source: Magoosh

20% of the 300 male employees have advanced degrees and 40% of the 100 females have advanced degrees
20% of 300 = 60. So, there are 60 MALES with advanced degrees
40% of 100 = 40. So, there are 40 FEMALES with advanced degrees
Total number of advanced degrees = 60 + 40 = 100
So, P(selected person has advanced degree) = 100/400 = 1/4
Also, P(selected person is female AND has a advanced degree) = 40/400 = 1/10
Also, P(selected person is female) = 100/400 = 1/4

What is the probability the selected employee has an advanced degree or is female?
P(A or B) = P(A) + P(B) - P(A and B)
So, P(employee has advanced degree OR employee is female) = P(employee has advanced degree) + P(employee is female) - P(selected person is female AND has a advanced degree)
= 1/4 + 1/4 - 1/10
= 2/4 - 1/10
= 2/5

Answer: D

Cheers,
Brent

BTGModeratorVI wrote: ↑

Thu Aug 27, 2020 12:13 pm

In a certain corporation, there are 300 male employees and 100 female employees. It is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 400 employees is chosen at random, what is the probability this employee has an advanced degree or is female?

A. 1/20
B. 1/10
C. 1/5
D. 2/5
E. 3/4

Answer: D

Solution:

Since 20% of the male employees have advanced degrees, 0.2 x 300 = 60 male employees have advanced degrees.

Notice that the number of employees who either have advanced degrees or is female is the sum of the number of female employees and the number of male employees with advanced degrees. Thus, the probability of selecting an employee who is either female or has an advanced degree is:

(100 + 60)/400 = 160/400 = 16/40 = 2/5

Answer: D

BTGModeratorVI wrote: ↑

Thu Aug 27, 2020 12:13 pm

In a certain corporation, there are 300 male employees and 100 female employees. It is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 400 employees is chosen at random, what is the probability this employee has an advanced degree or is female?

A. 1/20
B. 1/10
C. 1/5
D. 2/5
E. 3/4

Answer: D

Solution:

Since 20% of the male employees have advanced degrees, 0.2 x 300 = 60 male employees have advanced degrees.

Notice that the number of employees who either have advanced degrees or is female is the sum of the number of female employees and the number of male employees with advanced degrees. Thus, the probability of selecting an employee who is either female or has an advanced degree is:

(100 + 60)/400 = 160/400 = 16/40 = 2/5

Answer: D