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If \(y\) and \(z\) are positive integers such that \(\dfrac{y}{2z}=123.24,\) the remainder obtained when \(y\) is divide

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by Gmat_mission » Thu May 21, 2020 1:34 am
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If \(y\) and \(z\) are positive integers such that \(\dfrac{y}{2z}=123.24,\) the remainder obtained when \(y\) is divided by \(z\) is what percentage lesser than \(z?\)

A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined

[spoiler]OA=C[/spoiler]

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Re: If \(y\) and \(z\) are positive integers such that \(\dfrac{y}{2z}=123.24,\) the remainder obtained when \(y\) is di

by Scott@TargetTestPrep » Mon May 25, 2020 11:16 am
Gmat_mission wrote: ↑
Thu May 21, 2020 1:34 am
 If \(y\) and \(z\) are positive integers such that \(\dfrac{y}{2z}=123.24,\) the remainder obtained when \(y\) is divided by \(z\) is what percentage lesser than \(z?\)

A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined

[spoiler]OA=C[/spoiler]

Solution:

We see that y/z = 246.48 and y = 246.48z. Therefore, the remainder is 0.48z, which means the remainder is 48% of the value of z. So the remainder is 52% less than the value of z.

Answer: C

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