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If y = 2 + 2K and y≠0y≠0, then 1/y + 1/y + 1/y + 1/y = ?

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If y = 2 + 2K and y≠0y≠0, then 1/y + 1/y + 1/y + 1/y = ?

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If y = 2 + 2K and y ≠ 0, then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)

OA B

Source: GMAT Prep

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BTGmoderatorDC wrote:
If y = 2 + 2K and y ≠ 0, then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)

OA B

Source: GMAT Prep
Adding the given fractions we have:

4/y

Since y = 2 + 2k, we have:

4/(2 + 2k) = 4/[2(1 + k)] = 2/(1 + k)

Answer: B

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Hi All,

We're told that Y = 2 + 2K and Y ≠ 0. We're asked for the value of 1/Y + 1/Y + 1/Y + 1/Y. This question can be solved in a number of different ways, including by TESTing VALUES. Since we're adding four fractions with the SAME denominator, we can just use some basic Arithmetic and Algebra rules.

To start, when adding fractions with the same denominator, we add the numerators. For example

1/5 + 1/5 + 1/5 = 3/5

Here, we're adding 1/Y + 1/Y + 1/Y + 1/Y, so we end up with 4/Y. We're told that Y = (2 + 2K). Substituting that value in, we get...

4/(2+2K)

We can then simplify that fraction, giving us...

2/(1+K)

Final Answer: B

GMAT assassins aren't born, they're made,
Rich

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BTGmoderatorDC wrote:
If y = 2 + 2k and y ≠ 0, then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)
Given: y = 2 + 2k
Rewrite as: y/1 = (2 + 2k)/1
Flip both fractions to get: 1/y = 1/(2 + 2k)

So, 1/y + 1/y + 1/y + 1/y = 1/(2 + 2k) + 1/(2 + 2k) + 1/(2 + 2k) + 1/(2 + 2k)
= 4/(2 + 2k)
= 4/(2)(1 + k)
= 2/(1 + k)

Answer: B

Cheers,
Brent

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BTGmoderatorDC wrote:
If y = 2 + 2K and y ≠ 0, then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)
Let k=0, implying that y = 2 + 2*0 = 2.
Plugging y=2 into 1/y + 1/y + 1/y + 1/y, we get:
1/2 + 1/2 + 1/2 + 1/2 = 2.
The correct answer must yield a value of 2 when k=0.
Only B works:
2/(1+k) = 2/(1+0) = 2.

The correct answer is B.

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BTGmoderatorDC wrote:
If y = 2 + 2K and y ≠ 0, then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)
Source: GMAT Prep
$$\left. \matrix{
y = 2\left( {k + 1} \right) \hfill \cr
?\,\,:\,\,\,4\left( {{1 \over y}} \right) = {4 \over y}\,\, = f\left( k \right)\,\,\,\,\, \hfill \cr} \right\}\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,? = {4 \over {2\left( {k + 1} \right)}} = {2 \over {k + 1}}$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.

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