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If \(y = 2 + 2k\) and \(y\ne 0,\) then \(\dfrac1{y} + \dfrac1{y} + \dfrac1{y} + \dfrac1{y} = ?\)
A. \(\dfrac1{8+8k}\)
B. \(\dfrac2{1+k}\)
C. \(\dfrac1{8+k}\)
D. \(\dfrac4{8+k}\)
E. \(\dfrac4{1+k}\)
Answer: B
Source: GMAT Prep
A. \(\dfrac1{8+8k}\)
B. \(\dfrac2{1+k}\)
C. \(\dfrac1{8+k}\)
D. \(\dfrac4{8+k}\)
E. \(\dfrac4{1+k}\)
Answer: B
Source: GMAT Prep
