Squaring both sides of the first equation, we have:
(x + y)^2 = 2^2
x^2 + y^2 + 2xy = 4
Since we are given that x^2 + y^2 = 2, we have:
2 + 2xy = 4
2xy = 2
xy = 1
Answer: D
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RedeemIf \(x + y = 2\) and \(x^2 + y^2 = 2,\) what is the value of \(xy ?\)
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(x + y)^2 = 2^2
x^2 + y^2 + 2xy = 4
Since we are given that x^2 + y^2 = 2, we have:
2 + 2xy = 4
2xy = 2
xy = 1
Answer: D
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