If \(x \ne 0,\) does \(x\) have an odd number of factors?

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If \(x \ne 0,\) does \(x\) have an odd number of factors?

by M7MBA » Thu Nov 19, 2020 8:03 am

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If \(x \ne 0,\) does \(x\) have an odd number of factors?

(1) \(\sqrt{x}\) is an integer.

(2) \(x^2\) is an integer.

Answer: A

Source: Veritas Prep

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Source: Beat The GMAT — Data Sufficiency | Thu Nov 19, 2020 8:03 am

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