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If x is an integer and y = -2x - 8, what is the least value of x for which y is less than 9?

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by BTGModeratorVI » Thu Aug 20, 2020 7:14 am

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If x is an integer and y = –2x – 8, what is the least value of x for which y is less than 9?

(A) –9
(B) –8
(C) –7
(D) –6
(E) –5

Answer: B
Source: Nova
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Re: If x is an integer and y = -2x - 8, what is the least value of x for which y is less than 9?

by Brent@GMATPrepNow » Sat Aug 22, 2020 5:48 am
BTGModeratorVI wrote: ↑
Thu Aug 20, 2020 7:14 am
 If x is an integer and y = –2x – 8, what is the least value of x for which y is less than 9?

(A) –9
(B) –8
(C) –7
(D) –6
(E) –5

Answer: B
Source: Nova
In other words, find the smallest INTEGER value of x such that -2x - 8 < 9
Take: -2x - 8 < 9
Add 8 to both sides to get: -2x < 17
Divide both sides by -2 to get: x > -8.5 [NOTE: since we divided by a NEGATIVE value, we reversed the inequality symbol]
The smallest INTEGER that's greater than -8.5 is -8

Answer: B
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