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If x is a non-negative integer then find x?(Source:GMATINSIG

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by GMATinsight » Mon Oct 17, 2016 4:13 am
If x is a Non-Negative integer then find x?
(1) x^2−5x+6=0
(2) x^2=3x

(Source:www.GMATinsight.com)

Answer: option C
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Source: — Data Sufficiency |

by melguy » Mon Oct 17, 2016 5:19 am
1) x^2-5x+6=0
(x-3) (x-2) = 0
x = 3 or x = 2
Not Sufficient

2) x^2=3x
Divide both sides by x
x = 3
Sufficient
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by GMATinsight » Mon Oct 17, 2016 5:46 am
melguy wrote:1) x^2-5x+6=0
(x-3) (x-2) = 0
x = 3 or x = 2
Not Sufficient

2) x^2=3x
Divide both sides by x
x = 3
Sufficient
You answer is Incorrect because of a small mistake that you have made while solving the second statement

x^2=3x
You CAN'T divide both sides by x because x may be zero as well. You can only divide an equation by a variable when you know it's non zero

therefore, x^2=3x
i.e. x^2-3x = 0
i.e. x (x-3) = 0
i.e. x = 0 or 3 i.e.
NOT SUFFICIENT

Combining both statements
x=3
SUFFICIENT

Answer: Option C
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by Brent@GMATPrepNow » Mon Oct 17, 2016 7:06 am
NOTE: when we're told that a number is "non-negative," we must be careful not to conclude that the number is positive.
A non-negative number can be positive or it can equal 0

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by melguy » Mon Oct 17, 2016 8:03 am
Brent@GMATPrepNow wrote:NOTE: when we're told that a number is "non-negative," we must be careful not to conclude that the number is positive.
A non-negative number can be positive or it can equal 0

Cheers,
Brent
My bad! :oops:
Thanks for correcting me.
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