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If \(x > 0\) and \(y > 0,\) what is the value of \(x - 2y?\)
(1) \(16y^2=\dfrac{x^4-240}{y^2}\)
(2) \(x^2+4y^2=\dfrac{120}{x+2y}\)
Answer: C
Source: Manhattan GMAT
(1) \(16y^2=\dfrac{x^4-240}{y^2}\)
(2) \(x^2+4y^2=\dfrac{120}{x+2y}\)
Answer: C
Source: Manhattan GMAT
