BTGmoderatorDC wrote:
If triangles ABC and CDE are each equilateral, what is the sum of the perimeters of the two triangles?
(1) Line segment AE measures 25 meters.
(2) Side BC is 2/3 as long as side DE.
Statement 1:
Case 1: AC = 10 and CE = 15, with the result that AE = 10+15 = 25
In this case, ABC + CDE = (10+10+10) + (15+15+15) = 75.
Case 2: AC= 5 and CD = 20, with the result that AE = 5+20 = 25
In this case, ABC + CDE = (5+5+5) + (20+20+20) = 75.
Since the sum of the perimeters is the same in each case, SUFFICIENT.
Statement 2:
Case 1: BC = 10 and DE = 15, with the result that BC/DE = 10/15 = 2/3
In this case, ABC + CDE = (10+10+10) + (15+15+15) = 75.
Case 2: BC = 2 and DE = 3, with the result that BC/DE = 2/3
In this case, ABC + CDE = (2+2+2) + (3+3+3) = 15.
Since the sum of the perimeters is NOT the same in each case, INSUFFICIENT.
The correct answer is
A.
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