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If the width, depth, and length of a rectangle box were each decreased by 50%, by how many percent would the volume of the box decrease?
A. 12.5%
B. 25%
C. 50%
D. 75%
E. 87.5%
The OA is E.
We can assign values for length (L), width (B), and depth (H) and get the solution, thus
L = 10
B = 10
H = 10
V = 10x10x10 = 1000
50% reduction
L = 5
B = 5
H = 5
V = 5x5x5 = 125
(125/1000)*100 = 12.5% ie new volume is 12.5 % of old volume or 100 - 12.5 = 87.5% reduction in volume. Option E.
Has anyone another strategic approach to solve this PS question? Thanks!
A. 12.5%
B. 25%
C. 50%
D. 75%
E. 87.5%
The OA is E.
We can assign values for length (L), width (B), and depth (H) and get the solution, thus
L = 10
B = 10
H = 10
V = 10x10x10 = 1000
50% reduction
L = 5
B = 5
H = 5
V = 5x5x5 = 125
(125/1000)*100 = 12.5% ie new volume is 12.5 % of old volume or 100 - 12.5 = 87.5% reduction in volume. Option E.
Has anyone another strategic approach to solve this PS question? Thanks!
