If the surface area of a certain cube is 2400, what is its volume? A. 8000(√6)^3 B. 1000(√6)^3 C. 8000 D. 6400 E. 4000 The OA is C. We know that the surface area of a cube is 6s^2, then $$6s^2=2400\ \Rightarrow s^2=400\ \Rightarrow s=20$$ Also, we know that the volume of a cube is s^3, then $$s^3=20^3=8000$$ Experts, any suggestion about this PS question? Thanks in advance.

LUANDATO wrote:If the surface area of a certain cube is 2400, what is its volume? A. 8000(√6)^3 B. 1000(√6)^3 C. 8000 D. 6400 E. 4000 The OA is C. We know that the surface area of a cube is 6s^2, then $$6s^2=2400\ \Rightarrow s^2=400\ \Rightarrow s=20$$ Also, we know that the volume of a cube is s^3, then $$s^3=20^3=8000$$ Experts, any suggestion about this PS question? Thanks in advance. Hi LUANDATO. Your answer is good. This is the correct way to solve this PS question. Since a cube is formed by 6 faces that are squares, then 6L^2=2400 and therefore L=20. And the volume of a cube is L^3, hence the volume is (20)^3=8000. Therefore, the correct answer is the option C. I hope this answer also can help you. Regards.

BTGmoderatorLU wrote:If the surface area of a certain cube is 2400, what is its volume? A. 8000(√6)^3 B. 1000(√6)^3 C. 8000 D. 6400 E. 4000 Suppose we have a cube such that the length of each edge is x. Since there are 6 faces on the cube, and each face has an area of x^2, then the surface area is the sum of the 6 faces’ areas. Thus, we have: 6x^2 = 2400 x^2 = 400 x = 20 Thus the volume of the cube is 20^3 = 8000. Answer: C

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