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If the sum of 3 consecutive integers is 54, then what is the

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by BTGmoderatorDC » Fri Jul 27, 2018 6:51 pm

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If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?

a) 280
b) 292
c) 312
d) 320
e) 323
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by GMATGuruNY » Fri Jul 27, 2018 7:02 pm
BTGmoderatorDC wrote:If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?

a) 280
b) 292
c) 312
d) 320
e) 323
Average of the 3 consecutive integers = sum/quantity = 54/3 = 18.
For any set of consecutive integers, average = median.
Thus, the median of the 3 integers = 18, implying that the 3 integers are 17, 18, and 19.
Product of the smallest and largest = 17*19 = integer with a units digit of 3.

The correct answer is E.
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by Jeff@TargetTestPrep » Sat Aug 18, 2018 7:05 pm
BTGmoderatorDC wrote:If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?

a) 280
b) 292
c) 312
d) 320
e) 323
Since the sum of 3 consecutive integers is 54, the middle integer must be the average, which is 54/3 = 18. So the smallest integer must be 17 and the largest must be 19. So the product is 17 x 19 = 323.

Answer: E

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