If the positive square root of the product of 3 numbers ...

IMHO the answer is D

Let x y z be the 3 integers and let X be the biggest one.
beacase sqrt (xyz) = x
xyz = x^2

So yz = x i.e. the product of the smaller numbers is equal to the bigger number.

I. If x=12 then yz=12. SUFFICIENT

2. Says x+y+z=20
The only combination of integers I could find was 2,6,12 and hence the product of 2 small numbers is 12. SUFFICIENT.

So both are sufficient alone.
Did anyone find another combination of numbers that satisfies (2).

wilderness wrote:IMHO the answer is D

Let x y z be the 3 integers and let X be the biggest one.
beacase sqrt (xyz) = x
xyz = x^2

So yz = x i.e. the product of the smaller numbers is equal to the bigger number.

I. If x=12 then yz=12. SUFFICIENT

2. Says x+y+z=20
The only combination of integers I could find was 2,6,12 and hence the product of 2 small numbers is 12. SUFFICIENT.

So both are sufficient alone.
Did anyone find another combination of numbers that satisfies (2).

The GMAT maths section instructions indicate that all numbers used are real numbers unless otherwise specified...
In this question, there is no mention in the stem that the numbers in question are integers, therefore the second statement is not sufficient in itself.

IMO A is the answer... Please comment.

thanks for the correction

soo.. just for the record, it's NOT safe to assume that all GMAT numbers are integers?

tzink wrote:soo.. just for the record, it's NOT safe to assume that all GMAT numbers are integers?

No.