If T is a set of 35 consecutive integers, of which 17 are

BTGmoderatorLU wrote:Source: GMAT Prep

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is C

Since 17 integers are negative, 35 – 17 = 18 are non-negative. We are given that the 35 integers are consecutive, thus, they would start from –17 till 17. So, we have 17 negative integers, one zero, and 17 positive integers.

Thus, the sum of all the integers in T = (–17 – 16 ... –1) + 0 + (1 + 2 + ... + 17) = 0.

The correct answer: C

Hope this helps!

-Jay
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BTGmoderatorLU wrote:Source: GMAT Prep

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is C

If 17 of the numbers are negative, then 35 - 17 = 18 numbers are zero or greater. Thus, we have the consecutive integers from -17 to 17 (including 0), and thus, the sum is 0.

Answer: C