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(1 millimeter accumulation) * (1 hour)/(30 millimeters accumulation) * (3600 seconds)/(1 hour) = 3600/30 = 120 seconds.alanforde800Maximus wrote:If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?
a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120
Let's keep listing EQUIVALENT RATES until we get to 1 millimeteralanforde800Maximus wrote:If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?
a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120
Recalling that 1 hour = 3600 seconds, we can create the equation:alanforde800Maximus wrote:If snow accumulation increased at a constant rate of 30 millimeters per hour during a certain snowstorm, how many seconds did it take for snow accumulation to increase by 1 millimeter?
a) 1/120
b) 1/60
c) 1/20
d) 20
e) 120
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