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IF P is an integer, is p/18 an integer

Expert replies
by doclkk » Sat Jun 27, 2009 6:22 am
IF P is an integer, is p/18 an integer

1. 5P/18 is an integer
2. 6p/18 is an integer

My thoughts: [spoiler]I think I'm starting to get this. So because 5P is an integer, this would mean that the smallest number possible that P could be is 5*18 because 5 does not contain any of the same prime factors as 18.

On the other hand with 6P, because 6 already has a 2 and a 3 this is insufficient because to be divisible by 18, it would need a 2's 3's and a 2.

Picking numbers is a little clearer. 5*P = 5*18 (minimum) or 5*36. Both work. Whereas 6P, p could be 3 or it could be 18. (No / Yes) [/spoiler]

OA: A
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Source: — Data Sufficiency |

Re: IF P is an integer, is p/18 an integer

by rahulg83 » Sat Jun 27, 2009 6:31 am
doclkk wrote: Picking numbers is a little clearer. 5*P = 5*18 (minimum) or 5*36. Both work. Whereas 6P, p could be 3 or it could be 18. (No / Yes)

OA: A
I think you have explained yourself :)
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