If \(n\) and \(k\) are positive integers, then how many ordered pairs \((n, k)\) satisfy \(n!+8=2^k?\)

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by Gmat_mission » Tue Nov 10, 2020 7:50 am

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If \(n\) and \(k\) are positive integers, then how many ordered pairs \((n, k)\) satisfy \(n!+8=2^k?\)

A. 0
B. 1
C. 2
D. 3
E. Infinitely many

Answer: C

Source: GMAT Club Tests

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If \(n\) and \(k\) are positive integers, then how many ordered pairs \((n, k)\) satisfy \(n!+8=2^k?\)

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If \(n\) and \(k\) are positive integers, then how many ordered pairs \((n, k)\) satisfy \(n!+8=2^k?\)

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