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(1) Exactly 6 of his coins were minted in 1910 or 1920.
(2) Exactly 7 of his coins were minted in 1920 or 1930.
OA C
Source: GMAT Prep
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Statement 1.BTGmoderatorDC wrote: ↑Wed Oct 20, 2021 6:12 pmIf John has exactly 10 coins each of which was minted in 1910 or 1920 or 1930, how many of his coins were minted in 1920 ?
(1) Exactly 6 of his coins were minted in 1910 or 1920.
(2) Exactly 7 of his coins were minted in 1920 or 1930.
OA C
Source: GMAT Prep
Or you could have saved yourself some time and just linked to identical solution on this page: https://gmatclub.com/forum/if-john-has- ... l#p2526921swerve wrote: ↑Thu Oct 21, 2021 2:34 pmStatement 1.BTGmoderatorDC wrote: ↑Wed Oct 20, 2021 6:12 pmIf John has exactly 10 coins each of which was minted in 1910 or 1920 or 1930, how many of his coins were minted in 1920 ?
(1) Exactly 6 of his coins were minted in 1910 or 1920.
(2) Exactly 7 of his coins were minted in 1920 or 1930.
OA C
Source: GMAT Prep
Exactly \(6\) of his coins were minted in \(1910\) or \(1920.\)
But how many in \(1920?\)
All \(6, 5,4,3, \cdots\) Or nothing. Not Sufficient \(\Large{\color{red}\chi}\)
Statement 2.
Exactly \(7\) of his coins were minted in \(1920\) or \(1930.\)
But how many in \(1920?\)
All \(7,6,5, \cdots\) Or nothing at all. Not Sufficient \(\Large{\color{red}\chi}\)
Combining 1 and 2:
Let \(1910\) be \(A\)
\(1920\) be \(B\) and \(1930\) be \(C\)
\begin{align}
\begin{cases}
A+B=6 &\quad (1) \\
B+C=7 &\quad (2) \\
A+B+C=10 &\quad (3)
\end{cases}
\end{align}
Equating \((1) \& (3)\), we get
\(C=4\)
And from equation \((2) \& (3)\), we get
\(A=3\)
Therefore, \(B=3\)
So, \(3\) coins were minted in \(1920\) C
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