Problem Solving

$$Let\ 2x\ -1\ =\ y\ and\ x\ =\ \frac{\left(y\ +\ 1\right)}{2}$$
$$f\left(y\right)=4\ \left(\frac{\left(y\ +\ 1\right)}{2}\right)^2-\ 4\ \left(\frac{y\ +\ 1}{2}\right)-\ 8$$
$$f\left(y\right)=\left(y\ +\ 1\right)^2-\ 2\ \left(y\ +\ 1\right)-\ 8$$
$$f\left(y\right)=y^2+1\ \left(-2y\ -\ 2y\right)?\left(-2-\ 8\right)$$
$$f\left(y\right)=y^2\ -\ 9$$
If y = 5
$$f\left(5\right)=5^2\ -\ 9$$
f (5) = 25 - 9
f(5) = 16.

Option A is CORRECT.

Brent@GMATPrepNow wrote:If f(2x - 1) = 4x² - 4x - 8, then f(5) =

A) 16
B) 18
C) 36
D) 48
E) 72

\[f\left( {2x - 1} \right) = 4{x^2} - 4x - 8\]
\[? = f\left( 5 \right)\]
\[{\text{Take}}\,\,x = 3\,\,\,\,\left( {{\text{so}}\,\,{\text{that}}\,\,\,2x - 1 = 5} \right)\]
\[? = f\left( {2 \cdot \boxed3 - 1} \right) = 4 \cdot {\boxed3^2} - 4 \cdot \boxed3 - 8 = 16\,\,\,\,\]

The above follows the notations and rationale taught in the GMATH method.