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If \(\dfrac1{x}+\dfrac13+\dfrac14=1,\) then \(x =\)

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by VJesus12 » Tue Oct 20, 2020 2:39 am
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If \(\dfrac1{x}+\dfrac13+\dfrac14=1,\) then \(x =\)

A. \(2\)

B. \(\dfrac{24}{11}\)

C. \(\dfrac{12}5\)

D. \(5\)

E. \(6\)

Answer: C

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Re: If \(\dfrac1{x}+\dfrac13+\dfrac14=1,\) then \(x =\)

by Scott@TargetTestPrep » Tue Oct 27, 2020 9:04 am
VJesus12 wrote: ↑
Tue Oct 20, 2020 2:39 am
 If \(\dfrac1{x}+\dfrac13+\dfrac14=1,\) then \(x =\)

A. \(2\)

B. \(\dfrac{24}{11}\)

C. \(\dfrac{12}5\)

D. \(5\)

E. \(6\)

Answer: C

Solution:

Multiplying the equation by 12x, we have:

12 + 4x + 3x = 12x

12 = 5x

12/5 = x

Answer: C

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