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If \(\dfrac{x}{x+y}=6\) then \(\dfrac{y}{y+x} =\)

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by M7MBA » Wed May 20, 2020 7:47 am
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If \(\dfrac{x}{x+y}=6\) then \(\dfrac{y}{y+x} =\)

A \(-5\)
B \(\dfrac{5}{11}\)
C \(1\)
D \(\dfrac{11}{5}\)
E \(5\)

[spoiler]OA=A[/spoiler]

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Re: If \(\dfrac{x}{x+y}=6\) then \(\dfrac{y}{y+x} =\)

by anonylfc » Fri May 22, 2020 8:15 am
On simplifying the given equation we can conclude ->
=> x=6x+6y
=> -5x = 6y
=> x= -6y/5

Now to find y/y+x we simply substitute the value of x (in terms of y) into this equation.
=y/y+5
=y/[y+(-6y/5)]
=y/[y-(6y/5)]
=y/(-y/5)
=-5y/y = -5

Hope this is helpful. Please upvote if it is !
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Re: If \(\dfrac{x}{x+y}=6\) then \(\dfrac{y}{y+x} =\)

by Scott@TargetTestPrep » Sun May 24, 2020 7:32 am
M7MBA wrote: ↑
Wed May 20, 2020 7:47 am
 If \(\dfrac{x}{x+y}=6\) then \(\dfrac{y}{y+x} =\)

A \(-5\)
B \(\dfrac{5}{11}\)
C \(1\)
D \(\dfrac{11}{5}\)
E \(5\)

[spoiler]OA=A[/spoiler]

If we add x/(x + y) and y/(y + x), we will have a sum of 1:

x/(x + y) + y/(y + x) = 1

6 + y/(y + x) = 1

y/(y + x) = -5

Answer: A

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