BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

If d and e are positive integers, is d a multiple of 9?

Expert replies
by BTGModeratorVI » Thu Dec 03, 2020 2:55 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

If d and e are positive integers, is d a multiple of 9?

(1) 5e - 7 is a multiple of 9.

(2) d - 2 = 5e

Answer: C
Source: official guide
Join the discussion
Source: — Data Sufficiency |

BTGModeratorVI wrote:
Thu Dec 03, 2020 2:55 pm
If d and e are positive integers, is d a multiple of 9?

(1) 5e - 7 is a multiple of 9.

(2) d - 2 = 5e

Answer: C
Source: official guide
Target question: Is d a multiple of 9?

Statement 1: 5e - 7 is a multiple of 9
This statement provides no information about d
Statement 1 is NOT SUFFICIENT

Statement 2: d - 2 = 5e
It's easier to analyze the statement if we rewrite the equation as: d = 5e + 2
There are several values of d and e that satisfy this equation. Here are two:
Case a: d = 7 and e = 1. Since 7 is not a multiple of 9, the answer to the target question is NO, d is not a multiple of 9
Case b: d = 27 and e = 5. Since 27 is a multiple of 9, the answer to the target question is YES, d is a multiple of 9
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that 5e - 7 is a multiple of 9.
This means we can write: 5e - 7 = 9k (for some integer value of k)

Statement 2 tells us that d - 2 = 5e, which we can rewrite as: d = 5e + 2

KEY STEP: Take d = 5e + 2 and rewrite it as: d = 5e - 7 + 9

Aside: I did this because we have some very specific information about 5e - 7 (it equals 9k, for some integer value of k)

So, we have: d = 5e - 7 + 9
Which is the same as: d = (5e - 7) + 9
Now substitute to get: d = 9k + 9
Now factor out the 9 to get: d = 9(k + 1)
At this point, it's clear that d is a multiple of 9
The answer to the target question is YES, d is a multiple of 9
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

BTGModeratorVI wrote:
Thu Dec 03, 2020 2:55 pm
If d and e are positive integers, is d a multiple of 9?

(1) 5e - 7 is a multiple of 9.

(2) d - 2 = 5e

Answer: C
Source: official guide
1) \(5e - 7\) is a multiple of \(9\). Insufficient, there is no info for \(d\). \(\Large{\color{red}\chi}\)

2) \(d - 2 = 5e\) Insufficient, as it may or may not be, depending on values of \(d\) and \(e\). \(\Large{\color{red}\chi}\)
e.g., when \(e=1, d=7 \Longrightarrow d\) is not a multiple of \(9\)
but when \(e=5, d= 29 \Longrightarrow d\) is a multiple of \(9\)

Combining \(1\&2\)
Say, \(5e - 7 = 9x \Rightarrow 5e=9x+7\)

Hence, \(d-2 =9x+7 \Rightarrow d=9x+9 \Rightarrow d=9(x+1)\)
So, \(d\) definitely is a multiple of \(9\). Sufficient \(\Large{\color{green}\checkmark}\)

Therefore, C
Join the discussion